The vertex form of the function g(x)=40x-4x² is g(x) = 4(x + 5)² - 100, where the vertex lies at (-5, -100).
The general equation of a parabola is given as,
y = a(x-h)² + k
where,
(h, k) are the coordinates of the vertex of the parabola in form (x, y);
a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.
As we want to write a function g(x) = 40x + 4x² in vertex form, and we know that the vertex form of a parabola, with vertex at (h,k) is written as,
[tex]f(x) = a(x-h)^2 + k[/tex]
Also, the algebraic identity [tex](x + a)^2[/tex] is written as,
[tex](x + a)^2 = x^2 + 2ax + a^2[/tex],
Therefore, [tex]x^2 + 2ax[/tex] can be written as
[tex]x^2 + 2ax = (x + a)^2 - a^2[/tex]
Further, we try to write the g(x) in the vertex form it can be written as,
[tex]\begin{aligned}g(x) &= 4x^2 + 40x\\\\ &= 4[x^2 + 10x]\\\\ &= 4[(x + 5)^2 - 5^2]\\\\ &= 4(x + 5)^2 - 100\\\end{aligned}[/tex]
Hence, the vertex form of the function g(x)=40x-4x² is g(x) = 4(x + 5)² - 100, where the vertex lies at (-5, -100).
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