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If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the change in the internal energy of the system, in kJ

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asuwafohjames

The change in the internal energy of the system is 110 kJ.

What is internal energy?

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

  • ΔU = Q-W.................... Equation 1

Where:

  • ΔU = Change in internal energy
  • Q = Heat absorbed from the surroundings
  • W = work done by the system

From the question,

Given:

  • Q = 115 kJ
  • W = 45. 0 kJ

Substitute these values into equation 1

  • ΔU = 155-45
  • ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

Learn more about  change in internal energy here: https://brainly.com/question/4654659

afreeze2323

Answer:

110.0kJ

Explanation:

The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.

.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.

ΔE=q+w

In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.

ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ

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