The fourth and fifth term of this sequence is -30 and -10 respectively.
Data;
- first term (a) = -810
- common difference (r) = ?
Common Difference
The common difference in a geometric progression is the ratio between two successive terms.
Let's find the common difference in this sequence
[tex]r = \frac{-270}{-810} \\r = \frac{1}{3}[/tex]
The nth term of a geometric sequence is given as
[tex]T_n = ar^n^-^1\\[/tex]
The next two terms of this sequence will be 4th and 5th term.
The fourth term of this sequence is
[tex]T_4 = ar^4^-^1\\T_4 = -810 * (\frac{1}{3})^3\\ T_4 = -810 * \frac{1}{27}\\ T_4 = -30[/tex]
The fifth term of this sequence is
[tex]T_5 = ar^5^-^1\\T_5 = -810 * (\frac{1}{3})^4\\T_5 = -810 * \frac{1}{81} \\T_5 = -10[/tex]
The fourth and fifth term of this sequence is -30 and -10 respectively.
Learn more on geometric progression here;
https://brainly.com/question/12006112
