[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6774.50\\ P=\textit{original amount deposited}\\ r=rate\to 2.7\%\to \frac{2.7}{100}\dotfill &0.027\\ t=years\dotfill &22 \end{cases} \\\\\\ 6774.50=P[1+(0.027)(22)]\implies \cfrac{6774.50}{1+(0.027)(22)}=P\implies 4250=P[/tex]