write an equation for the point 4,3
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Answer:
y-3=3(x-4)
Step-by-step explanation:
Hi there!
We are given that a line intersects the points (4, 3), and (6, 9)
The slope of this line is 3
And we want to write an equation in point-slope form using (4, 3)
Point-slope form is written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
We already have one point of the equation filled out -- the [tex]y_1[/tex], which in this case, is 3;
Our current equation is:
[tex]y-3=m(x-x_1)[/tex] (n.b. I put m and [tex]x_1[/tex] as place holders)
Before we proceed though, let's label the values of the other things (m and [tex]x_1[/tex]) to avoid confusion:
[tex]x_1=4\\m=3[/tex]
Now we can substitute these into the equation:
y-3=3(x-4)
Hope this helps!
See more on writing equations in point-slope form here: https://brainly.com/question/1616074
Answer:
[tex]Hence,\ the\ equation\ is\ \fbox{$y-3=3(x-4)$}\[/tex]
Step-by-step explanation:
[tex]Given,[/tex]
[tex]points=\left(4,3\right)R\left(6,9\right)[/tex]
[tex]To\ find!-the\ equation\ of\ line.[/tex]
[tex]Solution:-We\ know\ that\ the\ slope\ of\ the.[/tex]
[tex]line\ is\ given\ by[/tex]
[tex]slope\left(m\right)=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{9-3}{6-4}=\frac{6}{2}=3[/tex]
[tex]The\ equation\ of\ line\ in\ point-slope\ form[/tex]
[tex]using\ the\ point\ \left(4,3\right)\ will\ be[/tex]
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-3=3\left(x-4\right)[/tex]
I hope this helps you
:)