[tex]\boxed{\tt \pink{Given:}}[/tex]
[tex]\red\star[/tex]Diameter of base of a cylinder = 20 cm.
[tex]\red\star[/tex]Height of cylinder = 5cm.
[tex]\\\\[/tex]
[tex]\boxed{\tt \pink{To~Find:}}[/tex]
[tex]\red\star[/tex]Volume of Cylinder.
[tex]\\\\[/tex]
[tex]\boxed{\tt \pink{Solution}}[/tex]
To find volume of Cylinder first we should know radius of Cylinder. We can get radius by diameter using this formula:-
[tex]\boxed{\rm Diameter = 2 radius}[/tex]
[tex]\\\\[/tex]
[tex]\hookrightarrow\sf Diameter = 2 radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow\sf 20= 2 radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow\sf \dfrac{20}{2}= radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow\sf \dfrac{2\times10}{2}= radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow \sf \dfrac{\cancel2\times10}{\cancel2}= radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow \sf \dfrac{1\times10}{1}= radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow \sf 10= radius[/tex]
[tex]\\[/tex]
[tex]\hookrightarrow \bf radius = \pmb{\blue{10 cm}}[/tex]
[tex]\\\\[/tex]
Now Finally Let's find volume of Cylinder.
we know:-
[tex]\boxed{\rm Volume ~ of ~ Cylinder = \pi radius^2 \times height}[/tex]
[tex]\\\\[/tex]
So:-
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi radius^2\times height\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi (10)^2\times 5\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi 10\times10\times5\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi 100\times5\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \pi\times 500\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \dfrac{22}{7}\times 500\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\sf Volume ~of ~Cylinder = \dfrac{11000}{7}\\[/tex]
[tex]\\\\[/tex]
[tex]\dashrightarrow\bf Volume ~of ~Cylinder =\pmb{\blue{1,571.4~cm}}\\[/tex]
[tex]\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc}\small\underline{\sf{\pmb{ \gray{More \: Formulae}}}} \\ \\ \bigstar \: \bold{CSA_{(cylinder)} = 2\pi \: rh}\\ \\\bigstar \: \bold{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bold{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bold{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar\: \bold{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bold{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bold{Volume_{(cube)} ={(side)}^{3} }\\ \\ \bigstar \: \bold{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bold{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\\bigstar \: \bold{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bold{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bold{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
