Step-by-step explanation:
[tex] \bf \blue{ \boxed{ \bf p = 4 \: \: and \: \: q = - 5 \Rightarrow pq = 4 \times ( - 5) = - 20}} [/tex]
3(p2q + pq2 - pq) - 6pq + 3pq2 =
3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =
3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =
3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =
-180 + 120 + 6 × (-20) =
-180 + 120 + (-120) =
-180 + 120 - 120 =
-60 - 120 = -180
Answer:
-180
Step-by-step explanation:
3 ( p2q + Pq2 - pq ) - 6 pq +3pq2
3 [(4)(2)(-5) + (4)(-5)(2) - (4)(-5)] -6 (4)(-5) +3(4)(-5)(2)
3(-40-40+20) + 120 -120
3(-60) +0
-180+0
-180
