The volume of phosphoric acid is mathematically given as
X= 75 mL of H3PO4
What is the volume of H2PO4 required?
Question Parameters:
Milliliters of 0.750 M H2PO4 are required to react with 250. mL of 0.150 M Ba(OH)2
Generally, the equation for the banlanced Chemical Reaction is mathematically given as
2 H3PO4 + 3 Ba(OH)2 ------> Ba3(PO4)2 + 6H2O
Therefore
The volume of phosphoric acid=[tex]\frac{3*2*250*150*3*1}{1*2*750}[/tex]
The volume of phosphoric acid=0.075 L of H3PO4
In conclusion, the volume of H2PO4 in mL is
The volume of phosphoric acid=75 mL of H3PO4
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