Respuesta :
Answer:
- C) The distance is the absolute value of the difference
Step-by-step explanation:
We are interested in the last two columns.
If we compare them we see that each value of the distance column is the absolute value of corresponding value of difference:
- a - b = 1, 5, - 3
- distance = 1, 5, 3
Corect choice is C
Answer:
The distance is the absolute value of the difference.
Step-by-step explanation:
Given table:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} a & b & a+b & a-b & \sf distance\\\cline{1-5} 1 & 2 & 3 & -1 & 1 \sf \: unit\\\cline{1-5} 4 & -1 & 3 & 5 & 5 \sf \: units\\\cline{1-5} -6 & -3 & -9 & -3 & 3 \sf \: units\\\cline{1-5}\end{array}[/tex]
The difference is column 4.
The distance is column 5.
The absolute value of a number is its positive numerical value. It is denoted by a vertical line either side of the real number.
For example, |5| means 'the absolute value of 5', and |-5| means 'the absolute value of -5'.
Taking the absolute values of the differences:
⇒ |-1| = 1
⇒ |5| = 5
⇒ |-3| = 3
Therefore, the distance is the absolute value of the difference.