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10) What volume of oxygen at STP must react with 5.8 L of hydrogen to form water?
(Hint: write and balance the reaction first)
The answer is 2.9L (I NEED THE STEPS)

Respuesta :

mickymike92

2.9 L of oxygen are required to react with 5.8 L of hydrogen at STP to form water.

What is the balanced equation of the formation of water?

Hydrogen gas and oxygen gas combines in a molar volume ratio of 2 : 1 to form water.

The equation of the reaction is given as follows:

  • 2 H2O + O2 ----> 2 H2O

Thus, twice the volume of hydrogen is required with a given volume of oxygen to form water.

If 5.8 L of hydrogen is available for reaction at STP, the volume of oxygen required all be half of 5.8 L.

Volume of oxygen required = 5.8 / 2 = 2.9 L

Therefore, 2.9 L of oxygen are required to react with 5.8 L of hydrogen at STP to form water.

Learn more about water formation at: https://brainly.com/question/5980987

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