Answer:
Pierre has £ 146 and
Alex has £ 106
Step-by-step explanation:
Let the money with Pierre be = p
Let the money with Alex = a
If Pierre gave Alex £20, they would have the same amount.
So, we should subtract £ 20 from p and add £ 20 to a
p - 20 = a + 20
p = a + 20 + 20
p = a + 40 ----------------(I)
If Alex gave Pierre £22, then Pierre would have twice as much as Alex.
p + 22 = 2*(a -22)
p + 22 = 2a - 44
p = 2a - 44 - 22
p = 2a - 66
p -2a = - 66 -----------------(II)
Substitute p = a + 40 in equation (II)
a + 40 - 2a = -66
a - 2a + 40 = -66
-a = - 66 - 40
-a = - 106
Multiply both sides by (-1)
[tex]\boxed{a = \£ \ 106}[/tex]
Substitute a = 106 in equation (I)
p = 106 + 40
[tex]\boxed{p = \£ 146}[/tex]
