Respuesta :

Eduard22sly

The mass of the sample to methane that contains 3.62×10²⁹ atoms of hydrogen is 4810631.24 g

Avogadro's hypothesis

6.02×10²³ atoms  = 1 mole of Hydrogen

How to determine the mass of Hydrogen

1 mole of Hydrogen = 2 g

Thus,

6.02×10²³ atoms  = 2 g of Hydrogen

Therefore,

3.62×10²⁹ atoms =  (3.62×10²⁹ × 2) / 6.02×10²³

3.62×10²⁹ atoms = 1202657.81 g of Hydrogen

How to determine the mass of methane

  • 1 mole of methane, CH₄ = 12 + (4×1) = 16 g
  • Mass of H in 16 g of CH₄ = 4 × 1 = 4 g

Thus,

4 g of Hydrogen is present in 16 g of methane.

Therefore,

1202657.81 g of Hydrogen will be present in = (1202657.81 × 16) / 4 = 4810631.24 g of methane

Thus, we can conclude that the mass of the sample of methane is 4810631.24 g

Learn more about Avogadro's number:

https://brainly.com/question/26141731

Otras preguntas