Convert the function from vertex form to standard form.
-1/2(x + 2)^2 - 3
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Answer:
[tex] -\frac{1}{2}x^2-2x-5 [\tex]
Step-by-step explanation:
To convert it to standard form, all you need to do is expand the square and simplify. This would get us to: [tex]-\frac{1}{2}(x^2 + 4x + 4) - 3[/tex] which simplifies further to [tex]-\frac{1}{2}x^2-2x-2-3[/tex] and combine the -2 and -3 to get [tex] -\frac{1}{2}x^2-2x-5 [\tex]
Hope this helps :)