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Height of a Toy Rocket A toy rocket (not internally powered) is launched straight up from the top of a building 50 ft tall at an initial velocity of 200 ft per sec. a. Give the function that describes the height of the rocket in terms of timet b. Determine the time at which the rocket reaches its maximum height and the maximum height in feet. c. For what time interval will the rocket be more than 300 ft above ground level? d. After how many seconds will it hit the ground?​

Respuesta :

MrRoyal

The height of the toy is an illustration of the height function

The function of the toy velocity

The given parameters are:

  • Initial velocity, Vo = 200 ft per sec
  • Initial height, H = 50 ft

The function of the height is calculated as:

h(t) = -16t² + Vot + H

This gives

h(t) = -16t² + 200t + 50

Hence, the velocity function is h(t) = -16t² + 200t + 50

The time of maximum height

In (a), we have:

h(t) = -16t² + 200t + 50

Differentiate

h'(t) = -32t + 200

Set to 0

-32t + 200 = 0

Subtract 200 from both sides

-32t = -200

Divide both sides by -32

t = 6.25

Substitute 6.25 for t in h(t)

h(6.25) = -16 *6.25² + 200 * 6.25 + 50

h(6.25) = 675

Hence, the time to reach the maximum height is 6.25 seconds and the maximum height is 675 feet

When the rocket will be at a height more than 300

This is represented as

h(t) >300

So, we have:

-16t² + 200t + 50 > 300

Subtract 300 from both sides

-16t² + 200t - 250 > 0

Using a graphical calculator, we have:

t = 11.09s and t = 1.41 s

Hence, the rocket will be at a height more than 300 at 11.09s and 1.41 s

When it will hit the ground?

This means that

h(t) = 0

So, we have:

-16t² + 200t + 50 = 0

Using a graphical calculator, we have:

t = 12.75

Hence, the rocket will hit the ground at 12.75s

Read more about height function at:

https://brainly.com/question/12446886

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