Determine the dimensions of the rectangle of largest area that can be inscribed in a semicircle of radius 3.
On = 31/2,w=
- 3/2
On - 3√2, w = 3/2
Oh = 12, w = 312
W
Oh=312. W = 2

Respuesta :

The dimensions to maximize the area must be:

  • length =  (√3)/2
  • width =  (√3)/2

How to get the dimensions of the rectangle?

The rectangle with the largest area that can be inscribed on a circle of radius 3, will be a rectangle whose diagonal is equal to the diameter of the circle, so we have:

√(x + y) = 6 units.

Where x and y are the dimensions of the rectangle. We also must have that:

  • x < 6 units
  • y < 6 units.

Now, because we have limits, the largest area (which is the product of x and y) happens when x and y have the same value x = y, then we have:

√(x + x) = 6 units.

√(2x) = 6 units.

x = (√3)/2 = y

So the rectangle is actually a square of side length =  (√3)/2

If you want to learn more about rectangles, you can read:

https://brainly.com/question/17297081