Respuesta :

2Mg + O² => 2MgO

according to stoichiometry:

[tex] \frac{no {}^{2} }{1} = \frac{nmgo}{2} [/tex]

[tex]nmgo = no {}^{2} \times 2 = 7.2 \times 2 = 14.4[/tex]

Note that n stands for the number of moles.