A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of 25.0 g/cm. this wheel is released from rest at the top of a hill 69.0 m high.

Respuesta :

For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as

w=118.6 rad/s

What is the angular speed?

Generally, the equation for the  Conservation of energy  is mathematically given as

K1+U1=K2+U2

Therefore

Mgh+0=0+(1/2)MV2+(1/2)Iω2

Where

M=m+6m

M=2rλ(π+3)

Therefore

[tex]2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2[/tex]

[tex]w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)[/tex]

w=118.6 rad/s

In conclusion, The angular speed is

w=118.6 rad/s

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