For a 42.0-cm-diameter wheel, consisting of a rim and six spokes,the angular speed is mathematically given as
w=118.6 rad/s
Generally, the equation for the Conservation of energy is mathematically given as
K1+U1=K2+U2
Therefore
Mgh+0=0+(1/2)MV2+(1/2)Iω2
Where
M=m+6m
M=2rλ(π+3)
Therefore
[tex]2r \lambda (\pi+3)gh=0.52r \lambda (\pi+3)(rw)2+(1/2)[(2 \pi \lambda r)r2+6( \lambda r)r2/3]w2[/tex]
[tex]w=\sqrt{[(\pi+3)*9.8*53/(0.42/2)2*(\pi+2)[/tex]
w=118.6 rad/s
In conclusion, The angular speed is
w=118.6 rad/s
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