Taking into account the reaction stoichiometry, f 66.38 g of potassium chloride reacts with fluorine and produces potassium fluoride and chlorine, 0.4452 moles of chlorine is produced.
In first place, the balanced reaction is:
2 KCl + F₂ → 2 KF + Cl₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 149.1 grams of KCl form 1 mole of Cl₂, 66.38 grams of KCl form how many moles of Cl₂?
[tex]amount of moles of Cl_{2} =\frac{66.38 grams of KClx1 mole of Cl_{2}}{149.1 grams of KCl}[/tex]
amount of moles of Cl₂= 0.4452 moles
Then, if 66.38 g of potassium chloride reacts with fluorine and produces potassium fluoride and chlorine, 0.4452 moles of chlorine is produced.
Learn more about the reaction stoichiometry:
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