The cone is an illustration of volumes
If the cone does not overflow what percent of the cone will be filled is 80%
From the complete question, the given parameters are:
The volume of the cone is:
V = 1/3πr²h
So, we have:
V = 1/3 * π * 2² * 10
Evaluate
V = 40π/3
The volume of the sphere is:
V = 4/3πr³
So, we have:
V = 4/3 * π * 2³
Evaluate
V = 32π/3
Divide the volume of the sphere by the volume of the cone, to determine the percentage filled
Percentage filled = 32π/3 ÷ 40π/3
Evaluate
Percentage filled = 0.8
Express as percentage
Percentage filled = 80%
Hence, the percentage filled is 80%
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