At 10°C :
Temperature (in Kelvin) :
[tex]\qquad \tt \dashrightarrow \: 10 + 273[/tex]
[tex]\qquad \tt \dashrightarrow \: 283 \: k[/tex]
Now,
Temperature in Kelvin (at 150° C)
[tex]\qquad \tt \dashrightarrow \:150 + 173[/tex]
[tex]\qquad \tt \dashrightarrow \:323 \: k[/tex]
Now, let's find the volume (x) [ assume pressure to be constant ]
[tex]\qquad \tt \dashrightarrow \: \dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}[/tex]
[tex]\qquad \tt \dashrightarrow \: \dfrac{3.8}{283} = \dfrac{x}{323}[/tex]
[tex]\qquad \tt \dashrightarrow \: \dfrac{3.8}{283} \times 323 = {x}[/tex]
[tex]\qquad \tt \dashrightarrow \: {x} \approx4.34 \: \: litres[/tex]