Answer:
x = 4.28
Step-by-step explanation:
[tex]Given,\ To\ find\ for\ x,[/tex]
[tex]Let\ c\ be\ the\ centre\ of[/tex]
[tex]Circle,\ where[/tex][tex]AD=22.4\ (Diameter)[/tex]
[tex]AC=\frac{22.4}{2}=11.2\ (radius)[/tex]
[tex]AB=8.8[/tex]
[tex]In\ \Delta\ ABC, Right\ angled\ at[/tex]
[tex]B.\ USing Pythagoras\ theovem[/tex]
[tex](AB)^2+(BC)^2=(AC)^2[/tex]
[tex](8.8)^2+(BC)^2=(11,2)^2[/tex]
[tex](BC)^2=125.44-77.44=48[/tex]
[tex]BC=\sqrt{48}=6.92[/tex]
[tex]E_c=x+y\ \ \ \ \(Where\ Fc\ is\ also\ radius\ of\ arcle[/tex]
[tex]\therefore\ \ \ \ \11.2=x+6.92[/tex]
[tex]x=11.2-6.92=4.28[/tex]
[tex]Hence,\ x=4.28\ is\ the\ answer.[/tex]
I hope this helps you
:)
