Answer:
Θ ≈ 98.5° , 261.5°
Step-by-step explanation:
using the identity
cosΘ = [tex]\frac{1}{sec0}[/tex] , then
cosΘ = [tex]\frac{1}{-6.743}[/tex] ≈ - 0.1483
since cosΘ < 0 then Θ is in 2nd and 3rd quadrants
Θ = [tex]cos^{-1}[/tex] (- 0.1483) ≈ 98.5° ← in 2nd quadrant
related acute angle = 180° - 98.5° = 81.5° , then
Θ = 180° + 81.5° = 261.5° ← in 3rd quadrant
