Answer:
y = 1, 1.319, 1.024, 0
Step-by-step explanation:
Given equation:
[tex]y=(1+x)\cos x[/tex]
[tex]\textsf{when}\:x=0:[/tex]
[tex]\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}[/tex]
[tex]\textsf{when}\:x=\dfrac{\pi}{6}:[/tex]
[tex]\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}[/tex]
[tex]\textsf{when}\:x=\dfrac{\pi}{3}:[/tex]
[tex]\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}[/tex]
[tex]\textsf{when}\:x=\dfrac{\pi}{2}:[/tex]
[tex]\begin{aligned} \implies y & =\left(1+\frac{\pi}{2}\right)\cos \left(\frac{\pi}{2}\right)\\\implies y & = 0\end{aligned}[/tex]
