The total number of Ca2+ ions and F- ions that are present in the cubic unit cell will be 4 and 8 respectively.
From the complete information, the number of Ca2+ at corners will be (8 × 1/8 = 1) and those a the center will be (6 × 1/2 = 3). Therefore, the total number of Ca2+ will be:
= 1 + 3 = 4
The total number of F- ions will be:
= 4 × 2 = 8
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