Answer:
[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
Explanation:
Given equation:
[tex]A+3B \rightarrow \: C [/tex]
To find:
Limiting reactant for corresponding number of moles=?
Solution:
We know that the liming reactant is any atom, ion or molecule which is completely consumed during a reaction and other reactant is still left in reactant vessel.
For the given reaction A+3B→C
for every one mole of A three moles of B are required.
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in A) there is one mole of A and 4 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
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in B) there is 2 mole of A and 3 mole of B,
if 1 mole of A will react with 3 moles of B, 1 mole of A will be still there in reaction, the reactant was completely consumed is B which is limiting reactant.
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in C) there is 0.5 mole of A and 1.6 mole of B
if one mole of A requires three moles of B to complete the reaction then,
0.5 moles of A will require 1.5 moles of B
if 0.5 mole of A will react with 1.6 moles of B, 0.1 mole of B will be still there in reaction, the reactant was completely consumed is A which is limiting reactant.
﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌
in D) there is 24 mole of A and 72 mole of B
if one mole of A requires three moles of B to complete the reaction then,
24 moles of A will require 72 moles of B.
if 24 mole of A will react with 75 moles of B, 3 mole of B will be left over in reaction, the reactant was completely consumed is A which is limiting reactant.
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[tex]\fbox{ A) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ B) B \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ C) A \: is \: limiting \: reactant }[/tex]
[tex]\fbox{ D) A \: is \: limiting \: reactant }[/tex]
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