Trees that are cut down and stripped of their branches for timber are

approximately cylindrical. A timber company specializes in a certain type

of tree that has a typical diameter of 50 cm and a typical height of about

10 meters. The density of the wood is 380 kilograms per cubic meter, and

the wood can be sold by mass at a rate of $4. 75 per kilogram. Determine

and state the minimum number of whole trees that must be sold to raise

at least $75,000. *

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-04-14T15:44:21+02:00

From the calculations, the number of whole trees that can be sold at $75,000 is 21 trees.

Density is defined a the mass per unit volume. Now we have the following;

Diameter = 50 cm or 0.5 m

height = 10 meters

volume = ?

Density of the cylinder = 380 Kg/m^3

Now;

We can get the volume from;

V = πr^2h

V = 3.142 * (0.5/2)^2 * 10

V = 1.96m^3

From;

D = m/V

m = DV

m = 1.96m^3 * 380 Kg/m^3

m = 744.8 Kg

If 1 Kg of wood is sold at $4. 75

744.8 Kg is sold at 744.8 Kg * $4. 75/ 1 Kg

= $3537.8

Number of whole trees to be sold at $75,000= $75,000/$3537.8

= 21 trees

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