Answer:
[tex](x+4)^2+3=0[/tex]
Step-by-step explanation:
Hey there!
Standard form is what this equation is in
Standard form is this: [tex]ax^2+bx+c[/tex]
So order to complete the square, you need to take the [tex]b[/tex] term out of the equation, divide it by two, and then square it
In this case, the [tex]b[/tex] term is 8
We need to divide 8 by 2 ---> 4
Then square 4 ---> 16
So now you should add 16 to both sides
[tex]x^2+8x+16+19=16[/tex]
Now you can simplify the LHS
[tex](x+4)^2 +19=16[/tex]
Now you subtract 16 from both sides
[tex](x+4)^2+3=0[/tex]
So this is as far as you can go since you cannot take the square root of a negative number
