The moles of hydrogen which are produced from 57.5 grams of lithium is 8.21 grams.
Stoichiometry of the reaction gives idea about the relative amount of product produced by the reactant in terms of moles.
Given chemical reaction is:
2Li(s) + H₂O(l) → 2LiOH(aq) + H₂(g)
Moles of lithium will be calculated as:
n = W/M, where
n = 57.5 / 7 = 8.21 mol
From the stoichiometry of the reaction:
Mass of H₂ = (4.105mol)(2g/mol) = 8.21g
Hence required mass of hydrogen gas is 8.21g.
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