A parabola has focus (3,-2) and directrix y = 2. The point (a.-8) is on the parabola and its distance from the focus is 6 units.
The distance the point(x,y) from the focus(a, b) can be calculated as
[tex]\sqrt{(x-a)^2 +(y-b)^2}[/tex]
A parabola has focus (3,-2) and directrix y = 2. The point (a.-8) is on the parabola and its distance from directrix y = 2 will be y − 2
Hence equation would be
[tex]\sqrt{(a-3)^2 +(-8+2)^2}\\\\\sqrt{(a-3)^2 +(-6)^2}\\\\\sqrt{(3-3)^2 +(36)}\\\\\sqrt{ (36)}\\\\6[/tex]
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