Respuesta :
The RMS value of the current,phase angle and power dissipate will be 1191.51 ohm -89.01°,.283 watts respectively.
What is a capacitor?
A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.
The r.m.s. current is found as;
[tex]\rm X_L = 2 \pi f L \\\\ \rm X_L = 2 \times 3.14 \times 60 \times 35 \times 10^{-3} \\\\ X_L = 13.19\ ohm[/tex]
[tex]\rm X_C = \frac{1}{2\pi fC} \\\\X_C = \frac{1}{2 \times 3.14 \times 60 \times 20 \times 10^{-6}}\\\\ X_C=13.69 \ ohm[/tex]
[tex]\rm Z = \sqrt{R^2+(X_L-X_C)^2} \\\\ \rm Z = \sqrt{2^2+(13.19-13.26)^2} \\\\ Z= \sqrt{14284.25} \\\\ Z = 119.51 \ ohm[/tex]
The RMS value of the current is;
[tex]\rm I_{rms}=\frac{V_{rms}}{Z} \\\\ \rm I_{rms}=\frac{V_{45}}{119.51} \\\\ \rm I_{rms}=0.376\ ohm[/tex]
The phase angle and indicate if the current lags or leads the total voltage is;
[tex]\rm tan \theta =tan^{-1} \frac{X_L-X_C}{R} \\\\ \rm tan \theta =tan^{-1} \frac{13.19132.69}{119.51} \\\\ \theta = -89.01^0[/tex]
The power dissipate in this circuit is found as;
[tex]\rm P = IV cos \theta \\\\ \rm P = 0.376 \times 45 cos (-89.04) \\\\ P=0.376 \times 45 cos (-8904^0)\\\\ P=0.283 \ watt[/tex]
Hence, the power dissipate in this circuit is found is 0.283 watt.
To learn more about the capacitor, refer to the link;
https://brainly.com/question/14048432
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