Using the uniform probability distribution, it is found that the probabilities are given as follows:
1) 0.8 = 80%.
2) 0.0833 = 8.33%.
3) 0.3333 = 33.33%.
It is a distribution with two bounds, a and b, in which each outcome is equally as likely.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
Item 1:
10 minute interval, arrives in the 2nd minute, hence:
[tex]P(X > 2) = \frac{10 - 2}{10 - 0} = 0.8[/tex]
Item 2:
Within one inch of the end is greater than 11, hence:
[tex]P(X > 11) = \frac{12 - 11}{12 - 0} = 0.0833[/tex]
Item 3:
2 out of 6 numbers, hence:
p = 2/6 = 1/3 = 0.3333.
More can be learned about the uniform probability distribution at https://brainly.com/question/13889040
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