10 points, doing this one again because I got a wrong answer last time but regardless thank you for trying to help
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Hey ! there
Answer:
Step-by-step explanation:
In this question we are provided with a right angle triangle having TS - 35 ft and SE - 37 ft . And we are asked to find the missing side that is TE using Pythagorean Theorem .
Pythagorean Theorem : -
According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.
Where ,
Solution : -
In the given triangle ,
Now applying Pythagorean Theorem :
[tex] \quad \longmapsto \qquad \:SE {}^{2} = TS {}^{2} + TE {}^{2} [/tex]
Substituting values :
[tex] \quad \longmapsto \qquad \:37 {}^{2} = 35 {}^{2} + TE {}^{2} [/tex]
Simplifying it ,
[tex] \quad \longmapsto \qquad \:1369 = 1225 + TE {}^{2} [/tex]
Subtracting 1225 on both sides :
[tex] \quad \longmapsto \qquad \:1369 - 1225 = \cancel{1225} + TE {}^{2} - \cancel{1225}[/tex]
We get ,
[tex] \quad \longmapsto \qquad \:144 = TE {}^{2}[/tex]
Applying square root to both sides :
[tex] \quad \longmapsto \qquad \ \sqrt{ 144} = \sqrt{TE {}^{2}}[/tex]
We get ,
[tex] \quad \longmapsto \qquad \: \red{\underline{\boxed{\frak{TE = 12 \: feet}}}} \quad \bigstar[/tex]
Verifying : -
Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,
Substituting value of SE , TS and TE :
Therefore , our answer is correct .
[tex]\sf\large \green{\underbrace{\red{Answer⋆}}}:[/tex]
TE = 12 feet
Step-by-step explanation:
[tex] \textsf {\underline{ \large {To find :-}}}[/tex]
length of TE
[tex] \sf {\underline {\large {Given :-}}}[/tex]
TS = 35 feet
SE = 37 feet
[tex] \sf{ \green {\underline{ \underline {\huge{Solution :-}}}}}[/tex]
According to Pythagoras theorem
[tex] \sf \pink {hypotenuse^{2} = {perpendicular}^{2} + {base}^{2} }[/tex]
in the diagram
SE is our hypotenuse as it is front of 90°
TS is our perpendicular
TE is our base
So with the above formula we can find our base which is TE
[tex] \sf \implies {37}^{2} = {35}^{2} + {base}^{2} \\ \\ \sf \implies 1369 = 1225 + {base}^{2} \\ \\ \sf \implies 1369 - 1225 = {base}^{2} \\ \\ \sf \implies 144 = {base}^{2} \\ \\ \sf \implies \sqrt{144} = base \\ \\ \sf \implies { \fbox {\blue {12 = base}}}[/tex]
It's means our TE is 12 feet