The molarity of a solution made from 317.5g of AlCl3 with enough water to make 500.0 mL is 4.76M.
The molarity of a solution can be calculated by dividing the number of moles of the substance by its volume.
Molarity = no of moles ÷ volume
According to this question, a solution is made from 317.5g of AlCl3 with enough water to make 500.0 mL.
No of moles of AlCl3 = 317.5g ÷ 133.34 g/mol = 2.38 moles
Molarity of AlCl3 solution = 2.38 moles ÷ 0.5L
Molarity = 4.76M
Therefore, the molarity of a solution made from 317.5g of AlCl3 with enough water to make 500.0 mL is 4.76M.
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