At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 36 minutes and a standard deviation of 3 minutes. What is the probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes, to the nearest thousandth?

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raphealnwobi raphealnwobi · Answer 1 · 2022-05-13T12:03:14+02:00

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

An equation is an expression that shows the relationship between two or more numbers and variables.

Z score is given by:

z = (raw score - mean) / standard deviation

Given mean of 36 minutes and a standard deviation of 3 minutes.

For x = 32:

z = (32 - 36)/3 = -1.33

For x = 37:

z = (37 - 36)/3 = 0.33

P(-1.33 < z < 0.33) = P(z < 0.33) - P(z < -1.33) = 0.6179 - 0.0198 = 0.5981

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

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