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A 250 cm wire carrying a current of 9.0 A is at right angles to a uniform magnetic field. The force acting on the wire is 1.20N . What is the strength of the magnetic field

Respuesta :

Answer:

F = I L B     describes the perpendicular force on a wire of length L in a uniform field B

B = F / (I L) = 1.2 / (9 * 2.5) = .053 Tesla

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