The volume of the finely shredded paper that will be needed to completely fill the box with bowling balls to prepare for shipping is 2341 cubic inches.
It is defined as three-dimensional geometry when half-circle two-dimensional geometry is revolved around the diameter of the sphere that will form.
We have cubic box with edge length 17 inches
Volume of the cube = (side)³ = 17³ = 4913 cubic inches
As given, the bowling balls that are packaged are all the same size and are tangent to each other and the sides of the box
The radius of each ball will ball:
r = 17/4 inches
Volume of each(ball) sphere:
[tex]\rm V = \dfrac{4}{3}\pi r^3[/tex]
[tex]\rm V = \dfrac{4}{3}\pi (\dfrac{17}{4})^3[/tex]
V = 321.55 cubic inches
Volume for the 8 balls:
V = 8×321.55 = 2572.4 cubic inches
The total volume of finely shredded paper is:
V(s) = 4913 - 2572.4 = 2340.60 ≈ 2341 cubic inches
Thus, the volume of the finely shredded paper that will be needed to completely fill the box with bowling balls to prepare for shipping is 2341 cubic inches.
Learn more about the sphere here:
brainly.com/question/11374994
#SPJ1