17 in
17 in
A bowling ball manufacturer ships 8 bowling balls in a cubic box with edge length 17 inches, as shown. The bowling balls that are packaged are all the same size and are tangent to each other and
the sides of the box. To secure the bowling balls and prevent any damage during shipping, finely shredded paper is blown into all of the space not that is not taken up by the bowling balls. Which of
the following is closest to the total volume, in cubic inches, of finely shredded paper that will be needed to completely fill the box of bowling balls to prepare for shipping?

Respuesta :

The volume of the finely shredded paper that will be needed to completely fill the box with bowling balls to prepare for shipping is 2341 cubic inches.

What is a sphere?

It is defined as three-dimensional geometry when half-circle two-dimensional geometry is revolved around the diameter of the sphere that will form.

We have cubic box with edge length 17 inches

Volume of the cube = (side)³ = 17³ = 4913 cubic inches

As given, the bowling balls that are packaged are all the same size and are tangent to each other and the sides of the box

The radius of each ball will ball:

r = 17/4 inches

Volume of each(ball) sphere:

[tex]\rm V = \dfrac{4}{3}\pi r^3[/tex]

[tex]\rm V = \dfrac{4}{3}\pi (\dfrac{17}{4})^3[/tex]

V = 321.55  cubic inches

Volume for the 8 balls:

V = 8×321.55  = 2572.4 cubic inches

The total volume of finely shredded paper is:

V(s) = 4913 - 2572.4  = 2340.60 ≈ 2341 cubic inches

Thus, the volume of the finely shredded paper that will be needed to completely fill the box with bowling balls to prepare for shipping is 2341 cubic inches.

Learn more about the sphere here:

brainly.com/question/11374994

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