Answer:
[tex]\huge\boxed{\bf\:\frac{1}{10^{2}} = 10^{-2}}[/tex]
Step-by-step explanation:
Let's check all the equations.
[tex]\rule{150pt}{2pt}[/tex]
[tex]1^{0} = 0[/tex]
We know that, any number with 0 as its exponent will be equal to 1. Hence, this equation is incorrect.
[tex]\rule{150pt}{2pt}[/tex]
[tex](2^{5})^{5} = 2^{10}[/tex]
Let's solve the left hand side of the equation first.
[tex](2^{5})^{5}\\= 2^{5\times5}\\= 2^{25}[/tex]
We can see from this that,
[tex]2^{25} \neq 2^{10}[/tex]
Since, the left hand side [tex]\neq[/tex] right hand side, this equation is also false.
[tex]\rule{150pt}{2pt}[/tex]
[tex]\frac{1}{10^{2}} = 10^{-2}[/tex]
According to the identity ⟶ [tex]\bf\:\frac{1}{x^{y}} = x^{-y}[/tex], we can infer that the given equation is correct.
[tex]\rule{150pt}{2pt}[/tex]
So, the correct equation is [tex]\boxed{\bf\:\frac{1}{10^{2}} = 10^{-2}}[/tex].
[tex]\rule{150pt}{2pt}[/tex]