Jean and Jonathans' age illustrate arithmetic sum, and the sum of their ages in three years time is x + y + 6
Currently, their ages are:
Jean = x
Jonathan = y
In 3 years, their ages would be:
Jean = x + 3
Jonathan = y + 3
So, the sum of their ages is:
Sum = x + 3 + y + 3
Evaluate
Sum = x + y + 6
Hence, the sum of their ages in three years time is x + y + 6
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