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A 29.0-g sample of water at 290. K is mixed with 51.0 g water at 300. K. Calculate the final temperature of the mixture assuming no heat loss to the surroundings.

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ashish4112119

answer: 296 K

steps:

mass times temperature =mass times temperature

-51 * 300 = 29 * -290

300 * 51 = 15300

290 * 29 = 8410

-51x + 15300 = 29x - 8410

51 + 29 = 80

15300 + 8410 = 23710

23710 = 80x

80x = 23710

x = 296.375

https://socratic.org/questions/a-30-0-g-sample-of-water-at-280-k-is-mixed-with-50-0-g-of-water-at-330-k-how-wou

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