[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
let's evaluate the value of x ~
[tex]\qquad \sf \dashrightarrow \: \dfrac{3}{5} x + 10 = 17[/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{3}{5} x = 17 - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{3}{5} x = 7[/tex]
[tex]\qquad \sf \dashrightarrow \:x = 7 \cdot\dfrac{5}{3} [/tex]
[tex]\qquad \sf \dashrightarrow \:x = \dfrac{35}{3} [/tex]
or
[tex]\qquad \sf \dashrightarrow \:x \approx11.66[/tex]
