If the mean of the data set is 3.533. Then the mean absolute deviation for the data set will be 1.831.
Suppose the data specified is of n sized as
[tex]\rm x_1, x_2, \cdots , x_n[/tex]
Let this data's mean will be μ
Then, the mean absolute deviation of this data is the mean of the absolute differences of the observations from the mean of the data they belong to.
It is calculated as:
[tex]\rm M.A.D = \dfrac{\sum_{i=1}^n|x_i - \mu|}{n}[/tex]
The data set is given below.
3, 5, 6, 3, 2, 2, 1, 0, 0, 4, 7, 4, 5, 5, 6
Then the mean of the data will be
Mean = (3 + 5 + 6 + 3 + 2 + 2 + 1 + 0 + 0 + 4 + 7 + 4 + 5 + 5 + 6)/15
Mean = 53/15
Mean = 3.533
Then the mean absolute deviation for the data set will be
[tex]\rm M.A.D = \dfrac{|3-3.533| + |5-3.533| + |6 - 3.533| + |3 - 3.533| + ...+|6-3.533|}{15}[/tex]
M.A.D. = 27.4665/15
M.A.D. = 1.831111
More about the mean absolute deviation link is given below.
https://brainly.com/question/10258446
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