The equation of the straight line that passes through the point (3,5) which is perpendicular to the line y = 3x + 2 is x -3y -18=0
What is an equation?
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
To find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y = 3x + 2, we will first find the slope(m).
To find the slope m of the perpendicular equation;
y = 3x + 2 --------------(1)
comparing the equation above with the standard equation of a circle
y=mx + c
m=3
The slope of the perpendicular equation;
= -1
3 = -1
Divide both-side of the equation by 3
= -1/3
so, the slope of our perpendicular equation is -1/3
Then, we go ahead to find our intercept
To find the intercept, we will plug in the points and the new slope into the formula y =mx + c
5 = -(3) + c
5 = -1 +c
Add one to both-side of the equation
5+1 = -1 + c + 1
6 =c
c=6
our intercept c is equal to 6
so we can now proceed to form our equation.
y = - x + 6
Multiply through by 3
-3y = -x + 18
We can rearrange the equation, hence;
x -3y -18=0
Therefore the equation of the straight line that passes through the point (3,5) which is perpendicular to the line y = 3x + 2 is x -3y -18=0
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