The class that had better overall results on the exam is class A.
The class with greater variablity in results is class B.
The statistics of students in class A:
Maximum score = 100
Minimum score = 65
Median = 85
First quartile = 1/4(n + 1) = 1/4 x 12 = 3rd term = 70
Third quartile = 3/4 x (n + 1) = 3/4 x 12 = 9th term = 90
The statistics of students in class B:
Maximum score = 100
Minimum score = 55
Median = 75
First quartile = 70
Third quartile = 80
The range would be used to determine which class has greater variability.
Range = highest score - lowest score
Class a = 100 - 65 = 35
Class B = 100 - 55 = 45
To learn more about range, please check: https://brainly.com/question/26348529
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