contestada

Calculate the amount of heat in kJ
required to increase the temperature of 45.0 grams of H2O from -14°C to 145°C?

SHOW ALL WORK

Respuesta :

  • mass=m=45g
  • ∆T=145-14=159°C
  • Specific heat=c=4.186J/g°C

Now

[tex]\\ \rm\Rrightarrow Q=mc\delta T[/tex]

[tex]\\ \rm\Rrightarrow Q=45(4.186)(159)[/tex]

[tex]\\ \rm\Rrightarrow Q=29950.83J[/tex]

[tex]\\ \rm\Rrightarrow Q=29.9KJ[/tex]

Use specific heat of wate as 1kcal/g°C

So

  • Q=mc∆T
  • Q=45(1)(145+14)
  • Q=45(159)
  • Q=7155cal

Otras preguntas