[tex]\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}[/tex]
Given,
Area = 225 yd²
Base = 30 yd
Height = [To be calculated]
To find:
The height of the given triangle.
We know that, area of a triangle is:
[tex] \frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd[/tex]
Therefore, the require height is 15 yd.
[tex]\green\star[/tex]Proof:
[tex] \frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2} [/tex]
[tex] \boxed{ \frak \red{brainlysamurai}}[/tex]
