Calcium carbonate (caco3) is an important component of coral reefs. how many moles are in 98.6 g of caco3? type in your answer using the correct number of significant figures. 98.6 g caco3 = mol caco3

Respuesta :

0.986 moles of CaO are formed when  98.60 g of [tex]CaCO_3[/tex]decomposes.

What are moles?

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others.

Number of moles of CaCO3 =[tex]\frac{mass}{molar \;mass}[/tex]

Number of moles of CaCO3 = [tex]\frac{98.60 g}{100 g/mol}[/tex]

= 0.986 moles

Reaction:

[tex]CaCO_3[/tex]   →  [tex]CaO + CO_2[/tex]

Since the reaction is 1:1:1.

So 0.986 moles of CaO are formed.

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