The probability that the point P lies outside the square is;1 - (2/π)
If a is the radius of the circle, then;
Area of the inscribed square = 2a²
Now, area of the circle is;
Area of circle = πa²
Thus, probability that the point lies outside the square is;
Area of between circle and square/area of circle
Area between circle and square = πa² - 2a² = a²(π - 2)
Thus;
P(the point lies outside the square) = a²(π - 2)/πa² = (π - 2)/π = 1 - (2/π)
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