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A steam vent releases an unknown gas along with the steam. The steam travels 1.56 times faster than the unknown gas what is the molar mass of the unknown gas? H20: 18.02 g/mol

I know the answer is 43.8 g/mol but can someone tell me how to show my work because I don’t know where to start

Respuesta :

Eduard22sly

The molar mass of the unknown gas, given the data from the question is 43.8 g/mol

Graham's law of diffusion

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

How to determine the molar mass of the gas

  • Rate of unknown gas (R₁) = R
  • Rate of H₂O (R₂) = 1.56R
  • Molar mass of H₂O (M₂) = 18.02 g/mol
  • Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

R / 1.56R = √(18.02 / M₁)

1 / 1.56 = √(18.02 / M₁)

Square both side

(1 / 1.56)² = 18.2 / M₁

Cross multiply

(1 / 1.56)² × M₁ = 18.02

Divide both side by (1 / 1.56)²

M₁ = 18.02 / (1 / 1.56)²

M₁ = 43.8 g/mol

Learn more about Graham's law of diffusion:

https://brainly.com/question/14004529

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