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Select the correct answer from each drop-down menu. the number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is . the probability that both the first digit and the last digit of the three-digit number are even numbers is .

Respuesta :

The probability that both the first digit and the last digit of the three-digit number are even numbers will be 0.4 or 40%.

What is probability?

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The number of three-digit numbers with distinct digits can be formed using the digits 1, 2, 3, 5, 8, and 9.

Then the probability that both the first digit and the last digit of the three-digit number are even numbers will be

Total event = ⁶C₃ = 20

Favorable event = 8 {218, 238, 258, 298, 812, 832, 852, 892}

Then we have

P = 8/20

P = 0.4

P = 40%

More about the probability link is given below.

https://brainly.com/question/795909

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