The velocity in the first and the second case will be 1.8028 and 5.408 m/sec.
The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.
Given data:
Kinetic energy, KE=26 J
Mass,m=16 kg
The velocity is obtained as;
[tex]\rm KE= \frac{1}{2}mv^2 \\\\ v=\sqrt{\frac{2KE}{m} } \\\\ v=\sqrt{\frac{2 \times 26}{16} } \\\\v=1.8028 \ m/sec[/tex]
The second stone has mass and nine times the kinetic energy:
[tex]\rm KE= \frac{1}{2}mv^2 \\\\ v'=\sqrt{\frac{9\times 2KE}{m} } \\\\ v=\sqrt{9 \times \frac{2 \times 26}{16} } \\\\v=5.408 \ m/sec[/tex]
Hence the velocity in the first and the second case will be 1.8028 and 5.408 m/sec.
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